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#Playall sets how to
#Playall sets code

In any case, something lighter to start with. PlayStation is attempting to lean really hard into those in the future, having I guess “mastered” high quality single player games but having perilously few live games which print money in ongoing revenue.

#Playall sets how to

Past that, Bungie has been attempting to teach largely single player Sony studios on how to build a sustainable live service game in an industry when so many of those fail. There’s also rumblings that one of Sony’s new media projects could be a Destiny animated series. We should be a year or so away from at least the announcement of Bungie’s next, non-Destiny game, that is no doubt some sort of multiplayer live service offering. neither_sports = set_all - (set_C.On a more serious note, the real work of Bungie at PlayStation still feels like its only just begun. Students who don’t play any of the three sports : Here we just subtract the union of all the sets of players we received with the total set of players. only_two_sports = (set_C.intersection(set_F)-set_H).union((set_H.intersection(set_F)-set_C),(set_C.intersection(set_H)-set_F)) We get our answer by union-ing all the results. Lastly, we take the intersection of set of players who play football and cricket and then subtract the set of players who play hockey.Īs we can see, this leaves us with three sets of players that only play two sports. Secondly, we take the intersection of set of players who play cricket and hockey and then subtract the set of players that play football. Students who play exactly two of the sports : For this, we take the intersection of the set of players who play football and hockey and then subtract the set of players that play cricket.

c_and_f_but_not_h = (set_F.intersection(set_C)).difference(set_H) Students who play both cricket and football but don’t play hockey : We can take the intersection of the set of players who play football and the set of players who play cricket and then subtract the set of players that play hockey. all_three_sports = set_C.intersection(set_F,set_H) Students who play all the three sports : We can just take intersection of all 3 sets to give us the answer.

#Playall sets code

Working with the same question, I found that the lack of explanation with the answers made it difficult to understand what was going on so I'll post my code with an explanation of how I solved the problem. I am not sure if A is really needed or not.

Students who don’t play any of the three sportsģ lists containing numbers (ranging from 1 to 20) representing students who play cricket, football and hockey respectively.Ĥ different lists containing the students according to the constraints provided in the questions.

Students who play exactly two of the sports.

Students who play both cricket and football but don’t play hockey.

Based on this information, find out and print the following: You’re given three lists named ‘C’, ‘F’, and ‘H’, representing students who play cricket, football, and hockey, respectively. In a school, there are total 20 students numbered from 1 to 20. I tried to solve it, however, though I am getting the expected result the online validator is saying it as wrong. I am practicing it online and came across with the below problem.